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What is the area of the plates of a 2 farad parallel plate air capacitor, given that the separation between the plates is 0.5 cm?

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Solution :

Capacitance of a parallel capacitors. V=2F <br> Distance between the two plates , d=0.5 cm =`0.5xx10^(-2) m ` <br> capacitance of a parallel plate capacitor is given by the relation. <br> `C=(in_(0)A)/d` <br> `A=(Cd)/(in_(0))` <br> Where, `in_(0)`=Permitivity of free space =`8.85xx10^(-12) C^(2)N^(-1)m^(-2)` <br> ` :. A=(2xx0.5xx10^(-2))/(8.85xx10^9-12)=1130 km^(2)` <br> Hence , the area of the plates is too large. to avoid this situtation , the capacitance is taken in the range of `muF`.

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