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calculate the number of moleculesin each cubic metre of a gas at 1 atm and 27^(@)C.

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Solution :
We have `pV=NkappaT` <br> Or, `N=(pV)/(kappaT)` <br> `=((1.0xx10^(5)Nm^(-2))(1 m^3))/((1.38xx10^(-23)JK^(-1))(300K)) <br> ~~ 2.4xx10^(25).`

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