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Solution :

We have `p=(nRT)/(V)`. <br> The pressure due to oxygen is <br> `p_(1)=((0.1mol)(8.3JK^(-1) mol^(-1)(300K)))/((2000xx10^(-6)m^(-3))=1.25xx10^(5) Pa. <br> Similarly, the pressure in the vessel is <br> `p=p_(1)+p_(2)` <br> `=(1.25+2.50)xx10^(5)Pa=3.75xx10^(5)Pa.`